y^2-1.7y+0.7=0

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Solution for y^2-1.7y+0.7=0 equation: 


Simplifying
y2 + -1.7y + 0.7 = 0

Reorder the terms:
0.7 + -1.7y + y2 = 0

Solving
0.7 + -1.7y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-0.7' to each side of the equation.
0.7 + -1.7y + -0.7 + y2 = 0 + -0.7

Reorder the terms:
0.7 + -0.7 + -1.7y + y2 = 0 + -0.7

Combine like terms: 0.7 + -0.7 = 0.0
0.0 + -1.7y + y2 = 0 + -0.7
-1.7y + y2 = 0 + -0.7

Combine like terms: 0 + -0.7 = -0.7
-1.7y + y2 = -0.7

The y term is -1.7y.  Take half its coefficient (-0.85).
Square it (0.7225) and add it to both sides.

Add '0.7225' to each side of the equation.
-1.7y + 0.7225 + y2 = -0.7 + 0.7225

Reorder the terms:
0.7225 + -1.7y + y2 = -0.7 + 0.7225

Combine like terms: -0.7 + 0.7225 = 0.0225
0.7225 + -1.7y + y2 = 0.0225

Factor a perfect square on the left side:
(y + -0.85)(y + -0.85) = 0.0225

Calculate the square root of the right side: 0.15

Break this problem into two subproblems by setting 
(y + -0.85) equal to 0.15 and -0.15.


Subproblem 1
y + -0.85 = 0.15

Simplifying
y + -0.85 = 0.15

Reorder the terms:
-0.85 + y = 0.15

Solving
-0.85 + y = 0.15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '0.85' to each side of the equation.
-0.85 + 0.85 + y = 0.15 + 0.85

Combine like terms: -0.85 + 0.85 = 0.00
0.00 + y = 0.15 + 0.85
y = 0.15 + 0.85

Combine like terms: 0.15 + 0.85 = 1
y = 1

Simplifying
y = 1


Subproblem 2
y + -0.85 = -0.15

Simplifying
y + -0.85 = -0.15

Reorder the terms:
-0.85 + y = -0.15

Solving
-0.85 + y = -0.15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '0.85' to each side of the equation.
-0.85 + 0.85 + y = -0.15 + 0.85

Combine like terms: -0.85 + 0.85 = 0.00
0.00 + y = -0.15 + 0.85
y = -0.15 + 0.85

Combine like terms: -0.15 + 0.85 = 0.7
y = 0.7

Simplifying
y = 0.7


Solution
The solution to the problem is based on the solutions
from the subproblems.
y = {1, 0.7}

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